I'm studying coding to calculate the width by multiplying the base and height of the triangle and adding continue? at the end.
I tried to make it possible to leave the program if I put Y or Y after the continue and put another character.
int base, height;
char con;
double width;
while (1) {
printf("Base = ");
scanf_s("%d", &base);
printf("Height = ");
scanf_s("%d", &height);
width = (base * height) / 2;
printf("Triangle width = %.1lf\n",width);
printf("Continue? ");
scanf_s(" %c", &con);
if (con != 'Y' || 'y') break;
}
But what I want to do is leave the program when I type Y and y, but I can't implement both of them. Only Korean characters are implemented as above.
I wonder how I can get on the program if I put in other letters except Y and Y.
c
if (con != 'Y' || 'y') break;
We need to change the line above as below.
if (con != 'Y' && con != 'y') break;
Escape when con is not 'Y' and con is not (&&)
con!= 'Y' || 'y'
is
However, 'y'
is always interpreted as true. So the whole condition is always going to be true.
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