I am currently studying about the expression of the trinomial.
year=2000
val = 'It's leap year' if ((year%40) == 0) and ((year%100)!=0) or ((year%400)==0)
print(val)
If you type the code like this,
SyntaxError: invalid syntax
An error appears.
I was wondering if the grammar of the trinomial expression was wrong
#trinomial expression grammar
true_value if condition else false_value
I wrote it down according to this grammar.
#Write it like a grammar form
year=2000
val = 'It's leap year' if ((year%40) == 0) and ((year%100)!=0) or ((year%400)==0) else pass
print(val)
The error still appears.
SyntaxError: invalid syntax
I deleted everything because I was wondering if the "and" and "or" in the conditional sentence were the problem.
#and, or erase it all
year=2000
val = 'It's leap year' if ((year%40) == 0) else pass
print(val)
The error still appears.
SyntaxError: invalid syntax
I don't know why the trinomial expression doesn't work.
I would appreciate it if you could tell me how to apply the trinomial expression here!
python syntax-error
Personally, I don't like this kind of code because it's not intuitive.
To make it easier to see,
a = 1
b = '1'
if a > 0:
b = '2'
else:
b = '3'
=>
You have to change it like this.
a = 1
b = '1' if a > 0 else '3'
error?
The code you wrote is expressed as follows.
a = 1
if a > 2:
b = '2'
else:
pass
print(b)
# Error because b value is not determined
Extra
The currently created code appears to be a valid configuration when configured in this way.
import datetime
try:
datetime.datetime(2021, 2, 29)
print ('2021 is a leap year')
except:
pass
To explain more intuitively why errors occur in beginner's explanation
year=2000
val = 'It's leap year' if ((year%40) == 0) else pass
print(val)
val = pass when else in code.
The reason for the error is that the val does not contain a normal value.
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