I want to get url of the site that was opened on a separate tab by web operation using selenium.

Asked 2 years ago, Updated 2 years ago, 490 views

After opening the web in selenium, the user tried to get the url of the page opened by operating it.

 from selenium import webdriver
import time

browser=webdriver.Chrome('chromedriver.exe')
browser.get('https://kakolog.jp/q/')
while True:
    time.sleep(1)
    print(browser.current_url)

After opening the web with the code above, I clicked on each thread, and it opened the page on a different tab, and I couldn't get the url for that page.

How can I get this url?

python selenium

2022-09-30 22:01

1 Answers

If you want to get the URL of the link, you can extract the href directly from <a target="_blank"...href="URL"> without clicking.
(See "#1. Read the first anchor from the element and get the URL" in the sample code.)
From there, driver.get can be used to transition without pop-up.

Also, if you want to retrieve or manipulate the URL of a tab that pops up after clicking, you can activate any tab in driver.switch_to.window.
(See "#2. Activate pop-up tab and get URL for active tab" in sample code)

Reference: How to get the URL "about:blank" from empty tab using selenium?

sample code:

 from selenium import webdriver
import chromedriver_binary
import time

driver = webdriver.Chrome('chromedriver.exe')
url='https://kakolog.jp/q/'

driver.get(url)
time.sleep(1)

# Get leading 'boxContainer item' element
element=driver.find_element_by_class_name('boxContainer.item')
# 1. Read the first anchor from the element and get the URL
anchor=element.find_element_by_class_name('link')
print(anchor.get_attribute('href'))

# retain the main tab window handle
main_tab=driver.current_window_handle

# Click the anchor to pop up
anchor.click()
time.sleep(1)

# 2. Activate the pop-up tab and obtain the URL of the active tab
new_tab=[x for x driver.window_handles if x!=main_tab][0]
driver.switch_to.window(new_tab)
print(driver.current_url)
time.sleep(1)

# Close the Active Tab
driver.close()
time.sleep(1)


2022-09-30 22:01

If you have any answers or tips


© 2024 OneMinuteCode. All rights reserved.