It's a question that was asked in the class assignment.
In order to create a procedure sqarray to store the square of element number i in data[i] for an integer array data, I programmed it as follows:
/*
ex1401.c
*/
# include <stdio.h>
void sqarray (int data[], int size)
{
inti;
for(i=0;i<size;i=i+1){
printf("%d", & data[i]);
}
}
void printIntArray(inta[], int size)
{
inti;
for(i=0;i<size;i=i+1){
printf("%d", a[i]);
}
printf("\n");
}
int main (void)
{
int data [100], n;
printf("n=? ");
scanf("%d", & n);
sqarray(data,n);
printIntArray(data,n);
return 0;
}
However, I received an error similar to the following:
ex1401.c:Infunction'sqarray':
ex1401.c:11:10:warning:format '%d' expectations argument of type 'int', but argument 2 has type 'int*' [-Wformat=]
printf("%d", & data[i]);
~^ ~~~~~~~~
%ls
"In the above indication, I thought ""%d"" would look like ""%ls"", so I fixed it, but I got an error again."
What's wrong with my program?
&data[i] should be fixed.
warning:format '%d' expectations argument of type 'int', but argument2 has type 'int*'
This warning is to note that the argument expected a value of type int but was actually passed a value of type int*.Now that you want to see the i element of the array data (probably for debugging?), &data[i] should be passed to printf instead of &data[i].
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