count=0
def plus(a):
a=a+1
print(a)
for i in range(3):
plus(count)
If you run it like this, 1,1,1 appears.
How do I make it 1,2,3?
The reason why 1 comes out 3 times...
count=0
def plus(a): # <-- (2) plus(0) executed
a=a+1 # --> (3) only variable a in plus() is changing, and count is unchanged
print(a) # --> (4) 1 Output
plus(count) # --> (1) at this point count = 0
plus(count) # --> (5) Count has never changed at this point, so count = 0, 1 output
plus(count) # --> (6) The count has never changed even at this point
If you use the global variable count to do what you want...
defplus(lastCount): #What this function does is:
NowCount = lastCount +1 # If you add a number, it'll be +1
print(nowCount) # Print that out
return nowCount #Returns the number you just printed.
count = 0 # Now specify the initial value of a particular variable and
For i in range (3): # When you turn the loop,
The count = plus(count) # function changes the value to +1 and is repeatedly executed.
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