2d_array=[0,0,0],[0,0,1],[0,0,0],[0,0,0]]
I would like to print the final result '(1,2)' from the list like above.
As a trial, I made a separate list, added each element to the array above, and then looked for 1, and I got the result that it was in the fifth place, but I couldn't get to (1, 2) from there.
Thank you for your cooperation.
If you like to use NumPy, you can use np.where to write:This method lists all the locations where the desired element is located.
>>import numpy as np
>>arr = [[0, 0, 0], [0, 0, 1], [0, 0, 0], [0, 0, 0], [0, 0, 0]]
>>>ind=np.where(np.array(arr)==1)
>>>ind
(array([1]), array([2]))
>>># or:
... (ind[0][0], ind[1][0])
(1, 2)
If you were to create a function with raw Python, for example, you could simply use a loop in to write:Here we find the first place that contains the desired element.
>>def find 2d(lst,elem):
... for i, row in enumerate (lst):
... for j, e in enumerate (row):
... if == elem:
... return i,j
... return-1,-1# This is what happens when there is no desired element.
...
>>arr = [[0, 0, 0], [0, 0, 1], [0, 0, 0], [0, 0, 0], [0, 0, 0]]
>>find2d(arr,1)
(1, 2)
Note, however, that both methods are misdetected if True is in the element (because in Python 3 it is True==1).
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