Do you want to continue java? It doesn't stop when I type N in the Y/N decision.

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class LoToi1 {
    public static void main(String[]args) {
            // Preparing to enter
        BufferedReader br = new BufferedReader (new InputStreamReader (System.in));
        System.out.println("Determines whether the year entered is a leap year.");
        for(;;){
        // Display messages
            System.out.println("Enter an integer in the Western calendar.");
            try{
                // Get information to enter
                String line = br.readLine();
                // Convert string to numeric value
                inta = Integer.parseInt(line);
                // Leap year decision processing
                if(a%4==0&a%100!=0||a%400==0){
                    System.out.println("Leap year".");
                } else {//Other actions
                    System.out.println("Not a leap year.");
                }
                System.out.println("Do you want to continue?Y/N");
                booleanyn=false;
                while(!yn){
                    String input = br.readLine();
                    if(input.equals("Y")||input.equals("y")}
                        yn = true;
                    } else if(input.equals("N")||input.equals("n")}
                        yn = false;
　　　　　　　　　　　      break;
                    } else{
                        US>System.out.println("Enter Y or N.");
                    }    
                }    
            } catch(IOExceptione){
                // Action to be taken when input/output fails
                e.printStackTrace();
            } catch(NumberFormatExceptione){
                // Exception handling when non-numeric values are entered
                System.out.println("Enter as an integer");
            }
        }
    }
}

break in else if; why doesn't it work?

java

2022-09-30 20:53

2 Answers

From the point of view of the question, I am trying to get out of the outer for() loop with break, but only through the most recent while(!yn) loop.

I don't use it very often, but it's solved by using labeled break.

public class LoToi1{
    public static void main(String[]args) {
        // Preparing to enter
        BufferedReader br = new BufferedReader (new InputStreamReader (System.in));
        System.out.println("Determines whether the year entered is a leap year.");
        outLoop:for(;;) {//label
            // Display messages
            System.out.println("Enter an integer in the Western calendar.");

            // abbreviation

            booleanyn=false;
            while(!yn){
                String input = br.readLine();
                if(input.equals("Y")||input.equals("y")}
                    yn = true;
                } else if(input.equals("N")||input.equals("n")}
                    yn = false;
                    break outLoop;//Break with labelling
                } else{
                    US>System.out.println("Enter Y or N.");
                }    
            }

            // abbreviation    
        } // end of for (;;)
    } // end of void main()
}

2022-09-30 20:53

The reason why the loop continues when break is placed is because
In this case, the break breaks the most recent while, and the upper for does not break.

booleanyn is a true or false value indicating whether to continue the large loop.

as follows:

booleanyn=true;
for (;yn;) {

for loop to be used for loop conditions.
Or

for(booleanyn=true;yn;){

as shown in

The while loop repeats until one of the YyNn is entered, so
When you enter one of the YyNn in an infinite loop, set the true or false value to yn to get out of the loop.

while(true){
    String input = br.readLine();
    if(input.equals("Y")||input.equals("y")}
        yn = true; // This is the default value, so it is not necessary.
        break;
    } else if(input.equals("N")||input.equals("n")}
        yn = false;
        break;
    } else {
        US>System.out.println("Enter Y or N.");
    }
}

2022-09-30 20:53

If you have any answers or tips

Popular Tags

python x 4647

android x 1593

java x 1494

javascript x 1427

c x 927

c++ x 878

ruby-on-rails x 696

php x 692

python3 x 685

html x 656