What should I do if I want Ruby to make only 26 alphabetic characters?
integer.to_s(26)
It will be a combination of numbers and alphabets.
How about tr("0-9a-p", "a-z") in String#tr.
0.to_s(26).tr("0-9a-p", "a-z")
# = > "a"
25.to_s(26).tr("0-9a-p", "a-z")
# = > "z"
26.to_s(26).tr("0-9a-p", "a-z")
# = > "ba"
Personally, I feel very uncomfortable when 0 becomes a^^;
I heard that this is the Excel column name conversion test site.
class Fixnum
def bijective_s(base=nil, offset=nil)
offset||='A'.ord#65
base||=26
value = self
result = [ ]
while value > 0
value - = 1
result<<(value%base+offset).chr
value/=base
end
result.reverse.join
end
end
0.biotic_s#=>"
1. bijective_s#=>"A"
26.biotic_s#=>"Z"
27.biotic_s#=>"AA"
53.bijective_s#=>"BA"
702.bijective_s#=>"ZZ"
703.bijective_s#=>"AAA"
No. I'm just trying to make a comeback.
When implemented as a function:
defdec26(num)
table=('a'..'z').to_a
num>25?dec26(num/26)+table [num%26]:table [num%26]
end
However, with the above method, the tables are stacked each time you recursion, so the following is less stressful:
defdec26(num)
(num>25?dec26(num/26):'')+('a'.ord+num%26).chr
end
I would appreciate it if you could give me an example of INPUT and OUTPUT.
In particular, if the specifications are not clear when the digits are moved forward, you may not be able to get the answer you want.
For the time being, I wrote a program a long time ago called Excel column name conversion problem, which is similar to Excel column counting (?)
Here's an example:
1=>A
26 = > Z
27 = > AA
16384 = > XFD
I think there is a lot of room for refactoring because I wrote this code a long time ago, but I will post it for your reference.
class ExcelColConv
AZ_LENGTH='Z'.ord-'A'.ord+1#26
OFFSET_NUM='A'.ord-1#64
# Numbers to Alphabet
def to_col_string(col_num)
convert_num',col_num
end
def convert_num(ret,n)
if n == 0
ret
else
quo,rem=excel_divmod n
convert_num(rem+OFSET_NUM).chr+ret,quo#recursive
end
end
def excel_divmod(n)
quo,rem=n.divmod AZ_LENGTH
rem==0?[quo-1,AZ_LENGTH]:[quo,rem]
end
end
conv = ExcelColConv.new
[1,26,27,16384] .each do|n|
str=conv.to_col_string(n)
puts"#{n}=>#{str}"
end
I have also written a blog about this issue, so please read it if you like.
Tried writing the Excel column name conversion problem in Ruby, Perl, C#, and F#
I wrote a simple hexadecimal conversion.
class Integer
def to_26_a
n = self
if n == 0
"a"
else
table=[*'a'..'z']
result=""
while > 0
result+=table [n%26]
n / = 26
end
result.reverse!
end
end
end
puts(0.to_26_a)#a
puts(1.to_26_a)#b
puts(25.to_26_a)#z
puts(26.to_26_a)#ba
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