The following issues have been raised at the university:
Create a program to find the median when the data is given as a list.
Replace the median with the variable median and display the value.Create without a median function.You can also use the sorted function.
I know I use if statements, but I can't think of a conditional expression that finds a median without using a function.I've been looking into it for three days, and I want to persevere and complete it on my own, but I haven't made any progress since then.Please give me a hint about the conditional expression.
Data to use
data1:2,3,2,5,1,4,6
data2—2,3,2,5,4,4,6,5
data3—64, 50, 57, 36, 43, 52, 58, 72, 65, 53, 30, 56, 85, 69, 50, 55, 45, 61, 43, 76
Some of the results in the document
x=data1[:]
print("Data to be used:",x)
print("Medium:",median)
If you want to implement it honestly, this is what it looks like.If Create without using a function to find the median then can I use the len() function?
def get_median(nums):
# sort a list in order of small size
sorted_nums = sorted(nums)
# If the list is empty, return 'None' and exit
length = len(sorted_nums)
if not length:
return None
# Divide the number by two and you get a median index.
anchor=length//2#`//` is devalued
If length %2!= 0:// If the number is odd, use the index as it is
return sorted_nums [anchor]
else:
# If the number is even, divide it by adding two values in the middle.
med1 = sorted_nums [anchor-1]
med2 = sorted_nums [anchor]
return(med1+med2)/2
x = [2,3,2,5,1,4,6]
print("Data to be used:",x)
print("Medium:", get_median(x))#3
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