I want to use the DB value obtained in php for chart.js data.

Asked 2 years ago, Updated 2 years ago, 111 views

Nice to meet you.
I'm a beginner at javascript, but I found chart.js as a relatively easy library to draw graphs and made a simple sample.
In practical use, I think it would be a requirement to set the values stored on the DB to the values in the graph, but I am not sure how to pass the values of the php-acquired arrays to chart.js.
When I search for it, the keyword ajax appears, but if you only want to see it when you open the page,

<?php
$js_ary=json_encode($db_ary);
?>
<script type="text/javascript">
<!--
    variable = JSON.parse('<?phpecho$js_ary;?>');
    (omitted below)

So, is it all right to pass the data in JSON format and process it?

I'm sorry to ask you such a complete amateur question, but I appreciate your cooperation.

javascript php json chart.js

2022-09-30 19:51

1 Answers

Should I just pass the data in JSON format and process it?

Even if it is not JSON, you can display the config 'data: [0,0,0,0,0], ', and so on by outputting echo.
Also, I fixed the display sample to display it from JSON data (fixed data) below.

var randomScalingFactor=function(){
			return Math.round (Math.random()*100);
		};

		varconfig = {
			type: 'pie',
			data: {
				datasets: [{
					data: [0,0,0,0,0],
					backgroundColor: [
						window.chartColors.red,
						window.chartColors.orange,
						window.chartColors.yellow,
						window.chartColors.green,
						window.chartColors.blue,
					],
					label: 'Dataset1'
				}],
				labels:
					"Red",
					'Orange',
					'Yellow',
					'Green',
					'Blue'
				]
			},
			options: {
				responsive —true
			}
		};

		window.onload=function(){
			varctx = document.getElementById('chart-area').getContext('2d');
			window.myPie=new Chart(ctx,config);
            varjsondata=JSON.parse('{"A":12, "B":20, "C":25, "D":21, "E":22}');
            config.data.datasets[0].data[0] = jsondata["A"];
            config.data.datasets[0].data[1] = jsondata["B"];
            config.data.datasets[0].data[2] = jsondata["C"];
            config.data.datasets[0].data[3] = jsondata["D"];
            config.data.datasets[0].data[4] = jsondata["E"];
            window.myPie.update();
        };

		document.getElementById('randomizeData').addEventListener('click', function(){
			config.data.datasets.forEach(function(dataset){
				dataset.data = dataset.data.map(function(){
					return randomScalingFactor();
				});
			});

			window.myPie.update();
		});

		varcolorNames=Object.keys(window.chartColors);
		document.getElementById('addDataset').addEventListener('click', function(){
			var newDataset={
				backgroundColor: [ ],
				data: [ ],
				label: 'New dataset' + config.data.datasets.length,
			};

			for (var index=0; index<config.data.labels.length;++index){
				newDataset.data.push(randomScalingFactor());

				varcolorName=colorNames [index%colorNames.length];
				var newColor=window.chartColors [colorName];
				newDataset.backgroundColor.push(newColor);
			}

			config.data.datasets.push(newDataset);
			window.myPie.update();
		});

		document.getElementById('removeDataset').addEventListener('click', function(){
			config.data.datasets.splice(0,1);
			window.myPie.update();
		});
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.7.2/Chart.bundle.min.js"></script>
<script src="http://www.chartjs.org/samples/latest/utils.js"></script>
<body>
	<divid="canvas-holder" style="width:100%">
		<canvas id="chart-area"></canvas>
	</div>
	<button id="randomizeData">RandomizeData</button>
	<button id="addDataset">AddDataset</button>
	<button id="removeDataset">RemoveDataset</button>
</body>

If I run the sample outside of the snippet (I don't throw out errors with snippets in my display environment, the snippet does not emit errors.

Uncaught TypeError: Cannot read property 'red' of undefined

displays the button

<button id="randomizeData">RandomizeData</button>
<button id="addDataset">AddDataset</button>
<button id="removeDataset">RemoveDataset</button>

before initializing (before displaying)
 document.getElementById ('xxxxxx') 

because you have already run .
window.onload=function(){} encloses getElementById and causes to move after the object is initialized.


2022-09-30 19:51

If you have any answers or tips


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