What is Swift could not find overload for 'init'?

Translating the error message freely

Playerscore type cannot be a String() argument

will be

If you want to focus only on the code presented away from the question, I think it's appropriate to rewrite it like this.

if firstRandomNumber>secondRandomNumber{
   playerscoretotal+=1
   self.playerscore.text=playerscore.description
}

Any type implementing the Printable protocol must return some string (String type) and the description must return.

The answer to the question is off the subject, but
playerscore.text is substituted with playerscore because of the error.

self.playerscore.text=String(playerscore)

The part of is

self.playerscore.text=String(playerscoretotal)

Isn't that what you are supposed to do?

I think that's all right.

self.playerscore.text="\"(playerscore)"