I don't know how to handle the sort method.

Asked 2 years ago, Updated 2 years ago, 39 views

This is a Ruby language question.
The sources are as follows:

x=["abc", "dejgk", "loqp" ]
px.sort {|a,b|a<=>b}#1 Processing
px.sort {|a,b|b<=>a}#2 Processing
# ["abc", "dejgk", "loqp"]
# ["loqp", "dejgk", "abc"]

How does the sort method work with the <=> operator evaluation?
The process I am thinking about is as follows, but it does not match the execution results and
I don't know what to do correctly.

処理 Processing
 "abc" <=> "deigk" Assessment-1 "abc" stored in array [0].Store "deigk" in array [1]
 Store "deigk" <=> "loqp" Assessment-1 "deigk" in array (1).Stored "loqp" in array [2].
 # ["abc", "dejgk", "loqp"]

処理 Processing
  "deigk" <=> "abc" Assessment 1 "abc" stored in array [1].Stored "deigk" in array [0].
  Store "loqp" <=>"abc" Assessment 1"abc" in array [2].Stored "loqp" in array [1].  
 #["deigk", "loqp", "abc"]

As this is the first time I have posted a question, I would appreciate it if you could do something.

That's all.
Thank you for your cooperation.

ruby

2022-09-30 19:25

1 Answers

Array#sort rearranges elements of an array according to the evaluation rules specified in the block.
Comparisons are not always made sequentially from the beginning of the array.In this example, when I tried it on hand, the comparisons were made in the following order:

<"dejgk"<=>"loqp","abc"<=>"dejgk"
"dejgk"<=>"loqp" , "abc"<=>"loqp", "abc"<=>"dejgk"

Users don't usually need to know the sort algorithm inside the sort method.
I think the sort algorithm used in Array#sort is called quick sort.


2022-09-30 19:25

If you have any answers or tips


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