If I input 10 numbers, I created a program that outputs the numbers I entered and sorted in ascending order, but it gets a little strange.

#include<stdio.h>
#define NUMBER10

void swap (int*px, int*py)
{
    int temp=*px;
    *px = *py;
    *py=temp;
}

void readIntArray(inta[], int size)
{
    inti;
    for(i=0;i<size;i=i+1){
        printf("%dth?", i+1);
        scanf("%d", & a[i]);
    }
}

void printIntArray(inta[], int size)
{
    inti;
    for(i=0;i<size;i=i+1){
        printf("%d", a[i]);
    }
    printf("\n");
}

void bsort (inta[], intn)
{
    inti,j;
    for (i=0; i<n-1;i++)
        for (j=n-1; j>i;j--)
            if(a[j-1]>a[j])
                swap(&a[j], &a[j-1]);
}

int main (void)
{
    inti;
    int data [i], point [NUMBER];
    printf("Please enter %d data.\n", NUMBER);
    for(i=0;i<NUMBER;i++){
        printf("%d:",i+1);
        scanf("%d", & point[i]);
    } 
    bsort(point, NUMBER);
    readIntArray (data, NUMBER);
    printIntArray(data, NUMBER);
   
    puts("Sorted in ascending order.");
    for (i=0; i<NUMBER;i++)
        printf("%d#:%d\n", i+1, point[i]);

    return 0;
}

$./a.out
Please enter 10 pieces of data.
Number one: 10
Number 2: 9
Number 3: 8
Number 4: 7
Number 5: 6
Number 6: 5
Number 7: 4
Number 8: 3
Number 9: 2
Number 10: 1
Number one? 10
2nd? 9
Third? Eight.
4th? 7th.
Number five? Number six.
6th? 5th?
7th? 4th?
Number eight? Number three.
9th? 2nd.
Number 10? One.
10 9 8 7 6 5 4 3 2 1 
Sorted in ascending order.
Number one: 1
Number two: two.
Number three: three.
Number four: four.
Number five: five.
Number 6: 6
Number 7: 7
Number 8: 8
Number 9: 9
Number 10: 10

$./a.out
Please enter 10 pieces of data.
Number one? 10
2nd? 9
Third? Eight.
4th? 7th.
Number five? Number six.
6th? 5th?
7th? 4th?
Number eight? Number three.
9th? 2nd.
Number 10? One.
10 9 8 7 6 5 4 3 2 1 
Sorted in ascending order.
Number one: 1
Number two: two.
Number three: three.
Number four: four.
Number five: five.
Number 6: 6
Number 7: 7
Number 8: 8
Number 9: 9
Number 10: 10