Three numbers that make the Python sum 10

I'm writing Python code and I'm thinking about how to approach it, so please give me your opinion. I'd appreciate it if you could give me a direction.

The code objective is to match the set value set_point.

set_point = 10

unit1 = 6, unit2 = 3, unit3 = 5

Unit1 can be controlled 0-100%: Mistakes between 0 and 6

Unit2 can only be 0n/off (0% or 100%): 0 or 3 only

Unit3 can be controlled by 10% : 0, 0.5, 1, ..., 5

For example, the goal is to have unit1=4.5 (75% output), unit2=3 (100% output), and unit3=3.5 (70% output) total of set_point.

This is one of the many cases.

But there are many cases and I'm worried about how to approach it. I don't know if I should use the decision tree... I thought about getting all the possible options for each unit and combining them, but as the number of units increases, it will take a long time to spin.

Please.

python

2022-09-20 19:26

2 Answers

It's not that hard to get the number of cases.

for unit2 in [ 0, 3 ]:
    for u3 in range(0, 51, 5):
        unit3 = u3/10
        unit1 = 10 - unit2 - unit3
        set_point = unit1 + unit2 + unit3
        print( unit1, '|', unit2, '|',  unit3, '||', set_point)

10.0 | 0 | 0.0 || 10.0
9.5 | 0 | 0.5 || 10.0
9.0 | 0 | 1.0 || 10.0
8.5 | 0 | 1.5 || 10.0
8.0 | 0 | 2.0 || 10.0
7.5 | 0 | 2.5 || 10.0
7.0 | 0 | 3.0 || 10.0
6.5 | 0 | 3.5 || 10.0
6.0 | 0 | 4.0 || 10.0
5.5 | 0 | 4.5 || 10.0
5.0 | 0 | 5.0 || 10.0
7.0 | 3 | 0.0 || 10.0
6.5 | 3 | 0.5 || 10.0
6.0 | 3 | 1.0 || 10.0
5.5 | 3 | 1.5 || 10.0
5.0 | 3 | 2.0 || 10.0
4.5 | 3 | 2.5 || 10.0
4.0 | 3 | 3.0 || 10.0
3.5 | 3 | 3.5 || 10.0
3.0 | 3 | 4.0 || 10.0
2.5 | 3 | 4.5 || 10.0
2.0 | 3 | 5.0 || 10.0

2022-09-20 19:26

I don't know exactly what you want, but if the set_point value is fixed, I think we can roughly apply the method below, so I'm writing it down.

import random
set_point = 10
unit1 = random.uniform(1,2,3,4,5,6)
unit2 = random.uniform(0,3)
unit3 = set_point - unit1 - unit2

2022-09-20 19:26

If you have any answers or tips

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