#include <iostream>
#include <string>
using namespace std;
int main() {
int arrayName[3] = { 1, 2, 3 };
cout << arrayName[2] << endl;
cout << "Array size is " << **arrayName**.size() << endl;
string input_string;
cout << "Type something: ";
getline(cin, input_string);
cout << "Hello, World." << endl;
cout << "This is what you typed: ";
cout << input_string << endl;
input_string.erase(input_string.begin() + 1, input_string.end() - 1);
cout << input_string;
return 0;
}
Why is it that the red line is drawn in the arrayName part shown above and the error keeps popping up?
I'd really appreciate it if you could answer me.
c++
Because arrayName
is a normal array.
For use with a.size()
, a
must be a classy variable, and there must be a size()
function in the member function.
cout << "Array size is " << **arrayName**.size() << endl;
If you want to print the length of the normal array, try changing the code above like below.
cout << "Array size is " << sizeof(arrayName)/sizeof(arrayName[0]) << endl;
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