Shaping the date using Python modules

Do you want to format data from the SQL database with python?
In this case, wouldn't it be possible to simplify the date using the module?
Also, I would like to round off 2.26 and mark it as 2.3%.

Before plastic surgery
[(datetime.date(2016, 7, 17), 2.26268624680273)]

After plastic surgery
Jully 17,2016—2.3% errors

python python3

2022-09-30 17:35

1 Answers

Since you are using Python 3, I think using the format method is the most natural.

The f option also makes it easy to specify the number of decimal places.

ls=[(datetime.date(2016, 7, 17), 2.26268624680273)]
fort, vinls:
    print("{}-{:1f}% errors".format(t.strftime("%B%d,%Y"),v))

Note: http://uxmilk.jp/40547

2022-09-30 17:35

If you have any answers or tips

Popular Tags

python x 4647

android x 1593

java x 1494

javascript x 1427

c x 927

c++ x 878

ruby-on-rails x 696

php x 692

python3 x 685

html x 656