No instance of constructor matching argument list.

Asked 2 years ago, Updated 2 years ago, 111 views

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <cstring>

using namespace std;

class MyFriendInfo
{
private:
    char* name;
       int age;
public:
    MyFriendInfo(const char* fname, int fage) : age(fage) {
        name = new char[strlen(fname) + 1];
        strcpy(name, fname);
    }
    void ShowMyFriendInfo() {
        cout << "Name: " << name << endl;
        cout << "Age:" <<age << endl;
    }
    ~MyFriendInfo() {
        delete []name;

    }
};

class MyFriendDetailInfo : public MyFriendInfo
{
private:
    char* addr;
    char* phone;

public:
    MyFriendDetailInfo(const char* fname, int fage, char* faddr, char* fphone) :MyFriendInfo(fname, fage) {
        addr = new char[strlen(faddr) + 1];
        phone = new char[strlen(fphone) + 1];
        strcpy(addr, faddr);
        strcpy(phone, fphone);
    }
    void ShowMyFriendDetailInfo() {
        ShowMyFriendInfo();
        cout << "Address: " << addr << endl;
        cout << "Phone: " << phone << endl;
    }
    ~MyFriendDetailInfo() {
        delete []addr;
        delete []phone;
    }
};

int main(void) {
    MyFriendDetailInfomyFriend ("Name", 23, "Address", "01075455778");
    myFriend.ShowMyFriendDetailInfo();
    return 0;
}

I'm studying with Yoon Sung-woo's C++ textbook, and an error message appears as the third line ("name") is red at the bottom. How can I solve it?

constructor

2022-09-20 19:10

2 Answers

The reason for the error is not because of "Name", but because of "Address" and "01075455778".

MyFriendDetailInfo(const char* fname, int fage, char* faddr, char* fphone) :MyFriendInfo(fname, fage)

Among the codes you uploaded, if you look at the constructor function of the MyFriendDetailInfo class above, fname is const char* and faddr and fphone are char*.

Faddr and fphone should also be written as const char* as shown below. I think it might have been a typo while typing the book code.

MyFriendDetailInfo(const char* fname, int fage, const char* faddr, const char* fphone) :MyFriendInfo(fname, fage)
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <cstring>

using namespace std;

class MyFriendInfo
{
private:
    char* name;
    int age;
public:
    MyFriendInfo(const char* fname, int fage) : age(fage) {
        name = new char[strlen(fname) + 1];
        strcpy(name, fname);
    }
    void ShowMyFriendInfo() {
        cout << "Name: " << name << endl;
        cout << "Age:" <<age << endl;
    }
    ~MyFriendInfo() {
        delete[]name;

    }
};

class MyFriendDetailInfo : public MyFriendInfo
{
private:
    char* addr;
    char* phone;

public:
    MyFriendDetailInfo(const char* fname, int fage, const char* faddr, const char* fphone) :MyFriendInfo(fname, fage) {
        addr = new char[strlen(faddr) + 1];
        phone = new char[strlen(fphone) + 1];
        strcpy(addr, faddr);
        strcpy(phone, fphone);
    }
    void ShowMyFriendDetailInfo() {
        ShowMyFriendInfo();
        cout << "Address: " << addr << endl;
        cout << "Phone: " << phone << endl;
    }
    ~MyFriendDetailInfo() {
        delete[]addr;
        delete[]phone;
    }
};

int main(void) {
    MyFriendDetailInfomyFriend ("Name", 23, "Address", "01075455778");
    myFriend.ShowMyFriendDetailInfo();
    return 0;
}


2022-09-20 19:10

It may depend on the version of the compiler you use, but now implicit type transformation issues a warning or error.

Please explicitly convert to char* as below.

MyFriendDetailInfomyFriend((char*)"Name",23,(char*)"Address",(char*)"01075455778"));


2022-09-20 19:10

If you have any answers or tips


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