YEAR_BEGIN=[1971, 1979, 1948]
YEAR_END=2016
VAR_list = {0:'sst', 1:'precip', 2:'air'}
for ivar in [i]:
VAR = VAR_list [ivar]
print('Variable', ivar, VAR)
if VAR == 'precip':
filei1 = DIR0 + VAR + '.mon.mean' + '.nc'
elif VAR == 'sst':
filei1 = DIR0 + VAR + '.mon.mean.nc'
elif VAR == 'air':
filei1 = DIR0 + VAR + '.mon.mean.nc'
else:
pass
clim_ref_year=1981
if ivar = 1
1971
elifivar=2
1979
else:
1948
timeskip=(clim_ref_year-YEAR_BEGIN[ivar])*nman-1
I want to turn the VAR_list loop and assign YEAR_BEGIN to each one, but it doesn't work.Do you have a solution?
python python3
If you try, you will probably get an error saying 'i' is not defined in the for loop.
I think you should check the basic grammar when you turn the for loop in order with the elements in the list and rewrite the code.
(VAR_list is a dictionary, but it's also literate, so you can loop it around.)
It's not an answer, but I hope it will be an opportunity to answer.
There were too many unclear points in the code provided, so I will answer only the last part of ↓.
I want to turn the VAR_list loop and assign YEAR_BEGIN to each one, but it doesn't work.Do you have a solution?
As for this, as MorningMushroom wrote, I can turn it around as for, but I think it's better because I can get the key and value at the same time by using items().
YEAR_BEGIN=[1971, 1979, 1948]
VAR_list = {0:'sst', 1:'precip', 2:'air'}
fork, vin VAR_list.items():
clim_ref_year=YEAR_BEGIN[k]
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