This is how the list is saved. all_list=[['frodo', 'fradi'], ['abc123']]
I want to calculate using the productCotton Hand over product (all_list[0], all_list[1]).
However, if the all_list is variable, product(all_list[0],all_list[1],...,all_list[n]) I want to hand over the factor like this.
What should I do?
python
def doSomething(*args):
for i in range(len(args)):
print(args[i])
doSomething(1)
doSomething(1,2)
doSomething(1,2,3)
doSomething(1,2,3,4)
doSomething(1,2,3,4,5)
list_of_lists = [ [1,2,3], [4,5,], [6] ]
I watched it several times. You want to use the code like product(all_list[0], all_list[1], ..., all_list[n]), right? But you can't write the code like that. I can't write it like that. You could write it, but you really have to force yourself to write it. And there's a reason why everything can't be done. This is Anti Pattern.
Don't write it like that. Just
Make it work as product(all_list) like someone else's answer.
After handing over the all_list itself to the function, look at the length of the all_list inside the function and handle it accordingly.
Please refer to the code below.
list1=[['frodo', 'fradi'], ['abc123']]
list2=[['aaa'],['bbb'],['ccc']]
list3=[]
def product(lists):
if len(lists)==2:
print ('What to do when there are 2 arguments')
elif len(lists)>2:
print ('What to do when there are more than 3 arguments')
product(list1)
product(list2)
product(list3)
product(list1)
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