I'm going to take one line from the data frame, calculate it, and assign it to the new list one by one.
If you look at it, only the number of rows 0 and 12 changes, but I don't know how to make it into a repeating sentence. There are up to 600 lines.
df1.iloc[0].to_list() ##Part to be modified
row0 = list(df1.iloc[0])
row0
row_sum = 0
for i in row0:
row_sum += 10**(i/10)
row_sum = 10*np.log10(row_sum)
row_sum = round(row_sum, 2)
print(row_sum)
arr = []
arr.append(row_sum)
print(arr)
#----------------------------------------------------------
df1.iloc[1].to_list()
row1 = list(df1.iloc[1])
row1
for i in row1:
row_sum += 10**(i/10)
row_sum = 10*np.log10(row_sum)
row_sum = round(row_sum, 2)
print(row_sum)
arr.append(row_sum)
print(arr)
#----------------------------------------------------------
df1.iloc[2].to_list()
row2 = list(df1.iloc[2])
row2
for i in row2:
row_sum += 10**(i/10)
row_sum = 10*np.log10(row_sum)
row_sum = round(row_sum, 2)
print(row_sum)
arr.append(row_sum)
print(arr)
I think we can do it mechanically. Check it out.
arr = []
for i in range(600):
#df1.iloc[i].to_list()
row = list(df1.iloc[i])
#row1
for e in row:
row_sum += 10**(e/10)
row_sum = 10*np.log10(row_sum)
row_sum = round(row_sum, 2)
print(row_sum)
arr.append(row_sum)
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