def solution(number, k):
num_s = str(number)
answer = ''
if k == 0:
return number
list1 = []
list_a = []
list_temp = []
for i in range(len(str(number))):
list1.append(int(num_s[i]))
num1 = len(list1) - k
while True:
max_num = 0
if len(list_a) == num1:
answer = ''.join(map(str,list_a))
return answer
if k == 0:
list_a = list_a + list1
answer = ''.join(map(str,list_a))
return answer
for i in range(k+1):
if list1[i] == 9:
max_num = 9
elif list1[i] >= max_num:
max_num = list1[i]
list_a.append(max_num)
temp = list1.index(max_num)
k = k - temp
list1 = list1[temp+1:]
I'm solving the programmers problem, but one test keeps showing a timeout. Where do you think it takes the most time here?
python algorithm
If you use while True, the code repeats indefinitely.
Therefore, you have to break the loop with the same command as break in the middle, but there are no commands to stop repeating except for two if statements.
I don't know what number and k values are, but I think there will be a problem in that part.
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