I'd like to include it.

With Python 3.8 and later, you can use := (walrus operator/ walrus operator) to write:

 num1 = 0
_ = [print(x-(num1:=num1+i)) for in num]

An implementation using itertools.accumulate() is likely.Please adjust the print output separately, as the calculation results can be obtained as a list.

import it tools

x,n = map(int, input().split())
num = [int(input()) for_in range(n)]

z = [x-n for n intertools.accumulate(num)]
print(z)