Question about the result value that appears when the list is not added to the Lambda function (python)


a=[1,2,3,4,5,6,7,8,9,9,1,5,4,32,2]

a=map(lambda x :x*10,a)
print(a)

I used the Lambda function to do the things on the list at once *10.

But if you don't put a list,

map object at 0x000002659B33DF10

Is that what it says?

I wonder what that result without a list means. Is it like a hexadecimal position??

Thank you for your reply. Have a great day!

python lambda list

2022-09-20 08:56

1 Answers

Try running the example below in the idle line by line. It's better to run on a computer that doesn't perform well.

>>> a = list(range(1000000))
>>> b = map(lambda x: x*10, a)
>>> c = list(b)
>>> a = list(range(100000000))
>>> b = map(lambda x: x*10, a)
>>> c = list(b)
>>> import time
>>> def func():
    t = time.time()
    a = list(range(100000000))
    print(f"assigning a (list) took {time.time()-t} sec")
    t = time.time()
    b = map(lambda x: x*10, a)
    print(f"assigning b (map) took {time.time()-t} sec")
    t = time.time()
    c = list(map(lambda x: x*10, b))
    print(f"assigning c (list of map) took {time.time()-t} sec")


>>> func()
assigning a (list) took 5.798054933547974 sec
assigning b (map) took 0.0 sec
assigning c (list of map) took 34.67618656158447 sec
>>>

2022-09-20 08:56

If you have any answers or tips

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