Underscore files are also printed in gulpfile.js.js

I build the front desk using gulp, jade, and compass.

 --jade
│   │ _ --_partial
│   │ _ --_banners.jade
│   │ _ --_breadcrumb.jade
│   │ _ --_fixed_header.jade
│   │ _ -- --_footer.jade
│   │ _ --_head.jade
│   │ _ --_header.jade
│   │ _ --_lists.jade
│   │ _ --_maps.jade
│   │ _ --_recommend.jade
│   │ _ --_second_banner.jade
│   │ _ --_sidebar.jade
│   │ _ --_top_banner.jade
│   │ _ --_top_search.jade
│   │ --_tweets.jade
│   in -- index.jade

I would like to output only index.html, but the _partial folder will also be output.

The following is gulpfile.js.

'use strict';
var gulp=require('gulp');
varcompass=require('gulp-compass');
var jade=require('gulp-jade');
varplumber = require('gulp-plumber');

gulp.task('jade', function(){
    gulp.src('./app/jade/**/*.jade')
    .pipe(plumber())
    .pipe(jade({
        pretty —true
    }))
    .pipe(gulp.dest('./dist/html'));
});

gulp.task('compass', function(){
    gulp.src('compass', function(){
        gulp.src('.app/sass/**/*.scss')
        .pipe(plumber())
        .pipe(compass({
            config_file: 'config.rb',
            comments: false,
            css: './dist/css/',
            pass: './app/sass/'
        }));
    });
});

gulp.task('watch', ['jade', 'compass', function(){
    gulp.watch('./app/jade/**/*.jade', ['jade']);
    gulp.watch('./app/sass/**/*.scss', ['compass']);
});

gulp.task('default', ['jade', 'compass']);

I would appreciate it if someone could let me know.
Thank you for your cooperation.

javascript node.js gulp

2022-09-30 14:31

2 Answers

In gulp.src, specify the path you do not want to retrieve using !.

var gulp=require("gulp");

gulp.task("build", function(){
  gulp.src(["source/**/*", "!source/_**/*", "!source/**/_*")
    .pipe(gulp.dest("build"));
});

If you run gulp build in the above state:

/
+ node_modules/
+ source/
|   +_partial/
|   | +_partial.html
|   | + partial.html
|   |
|   +_index.html
|   + index.html
|
+ build/
|   + index.html
|
+ gulpfile.js
+ package.json

2022-09-30 14:31

The gulp.src argument is processed by glob, so if you want to exclude files with _ across the head, you can simply write:

 gulp.task('jade', function(){
    gulp.src('./app/jade/**/!(_)*.jade')
    .pipe(plumber())
    .pipe(jade({
        pretty —true
    }))
    .pipe(gulp.dest('./dist/html'));
});

2022-09-30 14:31

If you have any answers or tips

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