include < stdio.h>
int main(void){
a=63, b=1, c=11, d=8, e=28;
d %= c += 5 - d--;
printf("%d %d %d %d %d", a,b,c,d,e);
return 0;}
Why does the value of d come to -1 when you turn the code to?
When calculating by hand, we got 7 but if we implement it as visual studio, we get -1.
I want to know how -1 comes out~
operator
d %= c += 5 - d--;
is the same as running the following two lines sequentially.
d%=(c+=5-d);
d--;
Then you can solve it as below.
d%=(c+=5-d); becomes d%=(c+=(-3) because d is 8, and c becomes is 11.
Therefore, the expression above is as follows.
d%=8;
d--;
Since d is 8, d%=8 will be 0, and then d-- will finally be -1.
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