I created it as follows, but the terminal stopped with the following conditions:
/*
ex1402.c
*/
# include <stdio.h>
void reverseIntArray(inta[], int size)
{
inti,t;
for(i=0;i<size/2;i=i+1){
/* Replace a[i] and a[size-1-i]*/
t = a[i];
a[i] = a[size-1-i];
a[size-1-i] = t;
}
}
void readIntArray(inta[], int size)
{
inti;
for(i=0;i<size;i=i+1){
printf("%dth?", i=i+1);
scanf("%d", & a[i]);
}
}
void printIntArray(inta[], int size)
{
inti;
for(i=0;i<size;i=i+1){
printf("%d", a[i]);
}
printf("\n");
}
int main (void)
{
int data [100], size;
printf("n=? ");
scanf("%d", & size);
readIntArray(data,size);
printIntArray(data,size);
reverseIntArray(data,size);
printIntArray(data,size);
return 0;
}
terminals:
$ccex1402.c
$ ./a.out
n = ?10
Number one? 1
There was no error on the terminal, so I didn't even know where it was wrong.
What should I do?
By the way, it seems that the execution example should be like this.
$./a.out
n = ?10
Number 0? 1
1st? 2nd.
2nd? 3rd.
Third? Four.
4th? 5th?
Number five? Number six.
6th? 7th.
Seventh? Eight.
8th? 9th.
Number nine? Number ten.
1 2 3 4 5 6 7 8 9 10
10 9 8 7 6 5 4 3 2 1
scanf("%d", & a[i]);
The cause is the scanf() format string, and if you set "%d" to "%d", you will be able to proceed.
If you specify "%d", you may want to leave a space after the number, but one of the many traps in scanf() does not finish typing spaces in the format string until you enter non-blank characters after spaces like 1a will not consume the last
for(i=0; i printf("%dth?", i=i+1);
When the last semicolon is present, this for statement loops only this.
If you want to repeat scanf("%d", & a[i]);, delete the semicolon at the end of the for statement.
If possible, surround it with {}.
for(i=0; i printf("%dth?", i=i+1){
scanf("%d", & a[i]);
}
Like this.
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