I would appreciate it if you could give me some advice.
The implementation below is Swift, but any language is fine.
It is implemented to determine the correct time from 12:00 to 11:00 if the time hand of the analog clock is given an angle (for example, if the angle is 0 degrees, the number 12 will be returned). I can't think of a pretty way to write it.What I think is the best thing right now is that I can give you time by using the dictionary like the one below to make the angle and time into a dictionary.
func AngleToTime(){
var test = [0:12, 30:1, 60:2, 90:3, 12:4, 150:5, 180:6, 210:7, 240:8, 270:9, 300:10, 330:11]
let test = 0
print("Now\(test[testtest])!) It's time!")
}
Ideally, I would like to make it a function, and if I receive int, which is an angle with an argument, I will have time as a result of the calculation.It's an hour hand now, so I can do something with the above implementation, but I don't want to be in trouble when it comes to minute or second hands.
javascript php java swift3
In the case of the hour hand, it is 30 degrees for an hour, so
hour=angleH/30
/* However, 12 o'clock shows midnight.
before printing if you want to display 12:00 instead of midnight
if hour == 0 {
hour=12
}
You may want to add .
*/
For long and short hands, 1 minute and 1 second is equivalent to 6 degrees, so
min=angleM/6
sec=angleS/6
is fine.
In the case of the hour hand, 1 degree is 2 minutes, so wouldn't it be okay to use Math.floor (angle x 2/60) (angle x 2% 60) minutes (special treatment only when 0)
For example, javascript looks like this
function func(v){
varm = v*2;
result.value=m?fill_zero(Math.floor(m/60), 2)+":"+fill_zero(m%60,2):"12:00";
}
function fill_zero(v,len){
v+="";
while (v. length <len)
v = "0" + v;
return v;
}<input type="number" value="0" step="1" min="0" max="359" id="degre" name="degre" onchange="func(this.value)">
<input type="time" value="12:00" id="result" name="result" readonly>
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