This is the person who asked me a question on here.I am writing to ask you to tell me the solution again.Thank you for your cooperation.
jsonFile.json
{
"Site Name 1": ["URL 11", "URL 12", "URL 13", ... "URL 1n",
"Site Name 2": ["URL21", "URL22", "URL23", ... "URL2n",
"Site Name 3": ["URL31", "URL32", "URL33", ... "URL3n",
...
"Site Name n": ["URLn1", "URLn2", "URLn3", ... "URLnn" ]
}
There are multiple site names in the key portion, each with a different URL.
import json
f=open("anidora.json")
datas=json.load(f)
keys=datas.keys()
values=datas.values()
d = [ ]
forking keys:
row = [ ]
for vin datas [k]:
row.append([v,k])
d.append(row)
d=list(zip(*d))
Forrind:
For vinr:
print('<li><a href=\"{0}\"target=\"_blank\">{1}</a>/li>'.format(v[0], v[1]))
#<li><a href="URL11" target="_blank">Site 1</a>/li>
#<li><a href="URL21" target="_blank">Site 2</a>/li>
#<li><a href="URL31" target="_blank">Site 3</a>/li>
#<li><a href="URL12" target="_blank">Site 1</a>/li>
#<li><a href="URL22" target="_blank">Site 2</a>/li>
#<li><a href="URL32" target="_blank">Site 3</a>/li>
#<li><a href="URL13" target="_blank">Site 1</a>/li>
#<li><a href="URL23" target="_blank">Site 2</a>/li>
#<li><a href="URL33" target="_blank">Site 3</a>/li>
I was satisfied with this result, but if the number of array values is large, the output was only halfway through.
For example: key: site name 18, value: 48 URLs, up to 23rd URL
For key: site name 18, value: 28 URLs, only the eighth URL was displayed.
d.append(row)
d=list(zip(*d))
There seems to be a change in the number of arrays during this time, but I don't know the cause.
Please tell me how to print all the sites and URLs even if they increase.
I am sorry to ask you again, but I would appreciate it if you could let me know.
How do you like this?
#!/usr/bin/env python3
# -*-coding:utf-8-*-
import json
with open("jsonFile.json") asf:
data=json.load(f)
sites=sorted(data)
while any(data.values()):
for site in sites:
if not data [site]:
continue
url=data[site].pop(0)
print(""<li><a href="{}" target="_blank">{}</a><"".".format(site, url))
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