I would like to convert the variable in [ ]uint to [ ]byte.
Is there a good solution...?
As the questions are unclear, the answers will vary depending on the results.
As Nobonobo said, please convert it into a loop
package main
import(
"fmt"
)
func UintSliceToByteSlice(us[]uint)[]byte{
b:=make([]byte,len(us))
for i,v: = range us {
b[i] = byte(v)
}
return b
}
funcmain(){
u: = [ ] uint {1,2,3}
b: = UintSliceToByteSlice(u[:])
fmt.Println(b)
}
The result is 1, 2, 3, and 4 bytes slices.
It depends on the endian.The results depend on how uint (uint32 or uint64) is stored in memory.The following is an example of a Big Endian used as a network byte order:
package main
import(
"bytes"
"encoding/binary"
"fmt"
"log"
)
funcmain(){
u: = [ ] uint {1,2,3,4}
var buf bytes.Buffer
for_,v: = range u {
err —=binary.Write (&buf,binary.BigEndian,uint32(v))
if err!=nil{
log.Fatal(err)
}
}
fmt.Println(buf.Bytes())
}
The result is [00 0 1 0 2 0 3 0 4 ].The size of uint varies depending on the platform, so if you can decide the size from the beginning, you can write it as follows.
package main
import(
"bytes"
"encoding/binary"
"fmt"
"log"
)
funcmain(){
u: = [ ] uint32 {1,2,3,4}
var buf bytes.Buffer
err: = binary.Write (&buf,binary.BigEndian,u)
if err!=nil{
log.Fatal(err)
}
fmt.Println(buf.Bytes())
}
© 2024 OneMinuteCode. All rights reserved.