To randomly generate a string

leng=int(input())

def gerRandomString(leng):
    import random
    num=random.randrange(97,123)
    for i in range(1,leng+1):
        num
    num=chr(num)
    word=[]
    for i in range(0,leng):
        word.append(num)
    b="".join(word)
    print(b)

gerRandomString(leng)

If you run it here, you'll get the same number of characters you've entered over and over again, but how do you get different characters to get the number you've entered? It doesn't matter if it's a duplicate character.

Example: abjunica at 8 input, and ackde at 5 input

python

2022-09-20 17:09

1 Answers

Python 3.8.5 (tags/v3.8.5:580fbb0, Jul 20 2020, 15:57:54) [MSC v.1924 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license()" for more information.
>>> chr(97)
'a'
>>> chr(123)
'{'
>>> [ chr(e) for e in range(97,123) ]
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
>>> import random
>>> random.sample('abcdefghijklmnopqrstuvwxyz', 3)
['z', 'c', 'q']
>>> l = 5
>>> random.sample('abcdefghijklmnopqrstuvwxyz', l)
['j', 'x', 'w', 'e', 'z']
>>> ''.join(random.sample('abcdefghijklmnopqrstuvwxyz', l))
'rmevu'
>>> l = 10
>>> ''.join(random.sample('abcdefghijklmnopqrstuvwxyz', l))
'dpilbfryth'
>>> ''.join(random.sample('abcdefghijklmnopqrstuvwxyz', l))
'jsnuwfvibl'
>>> l = 33
>>> ''.join(random.sample('abcdefghijklmnopqrstuvwxyz', l))
Traceback (most recent call last):
  File "<pyshell#12>", line 1, in <module>
    ''.join(random.sample('abcdefghijklmnopqrstuvwxyz', l))
  File "C:\PROGRAMS\Python3864\lib\random.py", line 363, in sample
    raise ValueError("Sample larger than population or is negative")
ValueError: Sample larger than population or is negative
>>> help(random.sample)
Help on method sample in module random:

sample(population, k) method of random.Random instance
    Chooses k unique random elements from a population sequence or set.

    Returns a new list containing elements from the population while
    leaving the original population unchanged.  The resulting list is
    in selection order so that all sub-slices will also be valid random
    samples.  This allows raffle winners (the sample) to be partitioned
    into grand prize and second place winners (the subslices).

    Members of the population need not be hashable or unique.  If the
    population contains repeats, then each occurrence is a possible
    selection in the sample.

    To choose a sample in a range of integers, use range as an argument.
    This is especially fast and space efficient for sampling from a
    large population:   sample(range(10000000), 60)

>>> help(random.choices)
Help on method choices in module random:

choices(population, weights=None, *, cum_weights=None, k=1) method of random.Random instance
    Return a k sized list of population elements chosen with replacement.

    If the relative weights or cumulative weights are not specified,
    the selections are made with equal probability.

>>> l = 33
>>> ''.join(random.choices('abcdefghijklmnopqrstuvwxyz', l))
Traceback (most recent call last):
  File "<pyshell#16>", line 1, in <module>
    ''.join(random.choices('abcdefghijklmnopqrstuvwxyz', l))
  File "C:\PROGRAMS\Python3864\lib\random.py", line 400, in choices
    cum_weights = list(_accumulate(weights))
TypeError: 'int' object is not iterable
>>> ''.join(random.choices('abcdefghijklmnopqrstuvwxyz', k=l))
'lrrhjwyjxjhmzzhznalkzfqsczrwaarzr'
>>> l = 10
>>> ''.join(random.choices('abcdefghijklmnopqrstuvwxyz', k=l))
'cdekxhpcil'
>>>

2022-09-20 17:09

If you have any answers or tips

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