import numpy as np
T_list = []
Temp_k = np.linspace(298, 398, 10)
#print (Temp_k)
current = np.linspace(0, 1.4, 5)
ppH2O = np.linspace(-2, -1, 5)
H2_pressure = []
H2O_pp = ppH2O
for i in (Temp_k):
print(i, 'i')
for j in (H2O_pp):
print(j, 'j')
for k in (current):
print (k, 'k')
partial_H2 = 5*np.exp((1.653 * k)/i) - 1/j
H2_pres1sure.append(partial_H2)
#print (H2_pressure)
Temp_k, H2O_pp, and current are defined as i, j,k, respectively.
partial_H2 = 5*np.exp((1.653 * k)/i) - 1/j
When this is the first value of Temp_k, H2O_pp, current, second, third... I'd like to get the last value as array or list, so what's the method?
For the current output, i = the first value j = the first value k = the first to the last value i = the first value j = the second value k = the first to last value
It comes out like this.
The way I want to get it is i = first j = first k = first i = second j = second k = second k ................................................ i = last j = last k = last
I'd like to get it this way.
python for
import numpy as np
T_list = []
Temp_k = np.linspace(298, 398, 10)
#print (Temp_k)
current = np.linspace(0, 1.4, 5)
ppH2O = np.linspace(-2, -1, 5)
H2_pressure = []
H2O_pp = ppH2O
for i in (Temp_k):
#print(i, 'i')
for j in (H2O_pp):
#print(j, 'j')
for k in (current):
#print (k, 'k')
partial_H2 = 5*np.exp((1.653 * k)/i) - 1/j
H2_pressure.append(partial_H2)
print(H2_pressure)
Is this what you want?
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