Counting the number of vowels in a sentence

import re

string = 'Creative Computing for Engineers, Architecture and Architectural Engineering'
vowel = len(re.compile('[aeiou]', re.I).findall(string))

I don't even want to write a sentence

If you look at the problem, it looks like you don't have to process any random sentence, you just have to count the number of vowels in the next sentence.

Creative Computing for Engineers, Architecture and Architectural Engineering

Therefore, the code below is a very fast and accurate code that meets the requirements of a given problem, but does not even require control of the while if structure.

def count_vowels_in_creative_computing_for_engineers_architecture_and_architectural_engineering() :
    return 28

# Working well
print(count_vowels_in_creative_computing_for_engineers_architecture_and_architectural_engineering())

Please submit this.